Find Nth max/min Salary in SQL server

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  1. SELECT * FROM temp1 t1 WHERE n - 1 = ( SELECT COUNT(DISTICNT ( sal )) FROM temp1 t2 WHERE t2.sal < t1.sal )
  2. SELECT TOP 1 * FROM ( SELECT DISTINT TOP n sal FROM temp1 ORDER BY sal DESC) AS t ORDER BY t.sal ASC
  3. In sql server 2005
    WITH MyCTE AS(
     SELECT t_id,
      sal,
      DENSE_RANK() OVER(ORDER BY sal DESC) as rank1
     FROM temp1
     )
    SELECT TOP 1 t_id, sal, rank1 FROM MyCTE WHERE rank1 = n

Any updates/comments are appreciated.

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